no of coin problem

/*
rita has a money pouch containing Rsx (for example 700). There are equal number of 25 paise coins, 
50 paise coins and one rupee coins. Write a C program to find out how many of each are there .
*/


/**************************
 *   author: umang bhatt  *
 * bhatt.umang7@gmail.com *
 **************************/

/*
what i ubderstood:
0.25 x + 0.50 x +  1 x = amt


so dividing everything by 0.25 we get
x + 2x + 4x = amt * 4

therefore 7x = 4 amt

*/

#include<stdio.h>
void main()
{

        int amt =700 ;
 int i;
 printf("Enter amount: " );

 scanf("%d",&amt);
        for( i = 1 ; i <= amt * 4 ; i++)
        {

                if( (7*i) == (4*amt) )
                {
                        printf("no of coins are: %d\n",i );

   break;
                }
  else if( (7*i) > (4*amt) )
                {

                        printf("no such combination of coins can exist\n" );
   break;
                }
        }
//       printf("\n%f\n", ( (0.25*i) +  (0.50 * i ) +  ( i) ));
}