no of coin problem

/*
rita has a money pouch containing Rsx (for example 700). There are equal number of 25 paise coins, 
50 paise coins and one rupee coins. Write a C program to find out how many of each are there .
*/


/**************************
 *   author: umang bhatt  *
 * bhatt.umang7@gmail.com *
 **************************/

/*
what i ubderstood:
0.25 x + 0.50 x +  1 x = amt


so dividing everything by 0.25 we get
x + 2x + 4x = amt * 4

therefore 7x = 4 amt

*/

#include<stdio.h>
void main()
{

        int amt =700 ;
 int i;
 printf("Enter amount: " );

 scanf("%d",&amt);
        for( i = 1 ; i <= amt * 4 ; i++)
        {

                if( (7*i) == (4*amt) )
                {
                        printf("no of coins are: %d\n",i );

   break;
                }
  else if( (7*i) > (4*amt) )
                {

                        printf("no such combination of coins can exist\n" );
   break;
                }
        }
//       printf("\n%f\n", ( (0.25*i) +  (0.50 * i ) +  ( i) ));
}

number operation

/**************************
 *   author: umang bhatt  *
 * bhatt.umang7@gmail.com *
 **************************/

/*
consider following number 45 * 45 = 2025; 20+25 = 45. Write a program
 to generate number between 32 and 99 the satisfies the abovce property.
*/


#include<stdio.h>

#define true 0
#define false 1
int foo(int n)
{
        int i = n * n;

        int j ;
        int return_val;
        j = i % 100;

        i = i / 100;
        if((i+j)==n)
        {

                return_val = true;
        }        
        else
        {
                return_val = false;
        }

        return return_val;
        
}
void main()
{
        int i ;

        for( i = 32 ; i <= 99 ; i++)
        {

                if(foo(i) == true )
                {
                        printf("%d ",i );
                }
        }

        printf("\n");
}