String pattern

/****************************
 *  Umang B Bhatt            *
 *   bhatt.umang7@gmail.com  *
 *****************************/

/**
 * program for string pattern
 */

/**
 * Enter string: Please      validate      my Input
 * Output:  Jnpvt my vbljdbtf Plfbsf
 */

/**
 * here all the words of a string are printed in reverse order (the last word comes first, second last wor comes second and so on)
 * here the order of words in the word is not changed.
 * whenever we encounter A, E , I , O or U replace it with the next character (eg A with B, E with F
 * and so on)
 * extra spaces in the program are also ignored
 */



#include<stdio.h>

#include<string.h>

void main()
{
    char arr[100][100] = {0};

    /* this trick also works with the structure
     * we can initialize whole structure using this technique
     */
    int x = 0, y = 0;

    char str[100];
    int i = 0;

    printf("\nEnter string: ");
    gets(str);
    /*asusual warnings with gets*/
    i = 0;

    while (str[i] != '\0' && i < strlen(str))
    {

        if (str[i] == ' ' || str[i] == '\0')
        {

            while (str[i] == ' ' && str[i] != '\0')
            {

                i++;
            }
        }
        else
        {
            if (str[i] == 'A' || str[i] == 'E' || str[i] == 'I' || str[i] == 'O' || str[i] == 'U' || str[i] == 'a' || str[i] == 'e' || str[i] == 'i' || str[i] == 'o' || str[i] == 'u')
            {

                arr[x][y] = str[i] +1 ;
                y++;

                i++;
            }
            else
            {
                arr[x][y] = str[i];

                y++;
                i++;
            }
            if (str[i] == ' ' || str[i] == '\0')
            {

                arr[x][y] = '\0';
                x++;
                y = 0;
            }

        }
    }

    printf("Output:");
    for (i = x; i >= 0; i--)
    {

        printf(" %s", arr[i]);
    }
    printf("\n");

}