sorting array in descending order

/****************************
*  Umang B Bhatt       *
*   bhatt.umang7@gmail.com  *
*****************************/

/**
 * program for scannign n numbers and sorting them in descending order
 */
#include<stdio.h>
void main()
{

 int n = 0 , i =0  , j = 0;

 int no[100];
 int temp; // for swapping the number
 printf("How many numbers you want to scan ? ");

 scanf("%d",&n);
 if(n < 0 || n>100)
 {

  printf("Invalid number. It must be brtween 1 to 100");
 }
 else
 {
  // logic for scanning the numbers
  for(i = 0 ; i < n ;i++)
  {

   printf("Enter element %d: ", i);
   scanf("%d",&no[i]);
  }

  
  // the logic for sorting the numbers
  for(i = 0 ; i < n ;i++)
  { 
   for(j = 0 ; j < n ; j++  ) 
   {

    if(no[i] > no[j])
    {
     // if the number at index i is greater than the number at index j then swap the numbers
     temp = no[i];

     no[i] = no[j];
     no[j] = temp;
    }
   }
  }

  for(i = 0 ; i < n ;i++)
  { 
   printf("\nnumber at index %d is %d ", i , no[i]);
  }
 }

 printf("\n");
}

scan n numbers and display them (using array)

/****************************
*  Umang B Bhatt       *
*   bhatt.umang7@gmail.com  *
*****************************/

/**
* program for scannign n numbers and displaying them
*/
#include<stdio.h>
void main()
{

 int n = 0 , i =0 ;

 int no[100];
 printf("How many numbers you want to scan ? ");
 scanf("%d",&n);

 if(n < 0 || n>100)
 {
  printf("Invalid number. It must be brtween 1 to 100");
 }

 else
 {
  // logic for scanning the numbers
  for(i = 0 ; i < n ;i++)
  {

   printf("Enter element %d: ", i);
   scanf("%d",&no[i]);
  }

  
  // the logic for displaying the numbers
  for(i = 0 ; i < n ;i++)
  {

   printf("\nnumber at index %d is %d ", i , no[i]);
  }
 }
 printf("\n");
}

pattern

A program that will generate above pattern:

#include<stdio.h>
// this program works well when the value of rows is less than 20
void main()
{

 int n = 5;
 int i = 0 , j = 0 , k = 0;

 int temp = 0 ;
 printf("Enter no of rows: ");

 scanf("%d",&n);
 temp = n;
 for(i = 0; i<n ;i++)
 {

  // logic for space
  for(k = 0 ; k < temp ; k++ )
  {

   printf("  ");
  }
  temp--;
  // for printing the actuak number
  for(j = 0; j <= i ; j++)
  {

   printf("%3d ", fun(i,j,n));
  }
  printf("\n");
 }
}

int fun(int a , int b, int n )
{

 int sum = 0 ;
 int i = 0 , j = 0;

 for(i = n-1 ; i >= 0 ; i--)
 {

  for(j = 0 ; j <= i ; j++)
  {

   sum++;
   if( i==a && b==j )
   {

    return sum;
   }
  }
 }
 return sum;
}

pattern

Question: Write a program that generates output shown in left image.

The code is:

#include<stdio.h>
// this program works well when the value of rows is less than 20
void main()
{

 int n = 5;
 int i = 0 , j = 0;

 printf("Enter no of rows: ");
 scanf("%d",&n);
 for(i = 0; i<n ;i++)
 {

  for(j = i; j >=0;j--)
  {

   printf("%3d ", fun(i,j));
  }
  printf("\n");
 }
}

int fun(int a , int b )
{
 int sum = 0 ;

 int i = 0 , j = 0;

 for(i = 0 ; i <= a ; i++)
 {

  for(j = 0 ; j <= i ; j++)
  {

   sum++;
   if( i==a && b==j )
   {

    return sum;
   }
  }
 }
 return sum;
}

1234 -> 4123 -> 3412number pattern

/*

Write a program that generated output something like this (here 1234 is input).
Here, keep all the numbers as integers only. Do not convert them to string or character:
1234
2341
3412
4123

note: here 0 will not be inputted at ay place
 */

import java.util.*;

public class a
{

    static int length(int n)
    {

        int len = 0;
        while (n > 0)
        {

            len++;
            n /= 10;
        }
        return len;
    }

    static int generate(int n)
    {
        int temp = (int) Math.pow(10, length(n) - 1);

        int temp2 = n / (int) Math.pow(10, length(n) - 1);

        temp = n % temp;
        temp = temp * 10;

        temp = temp + temp2;
        return temp;
    }

    public static void main(String a[])
    {
        int n;

        Scanner s = new Scanner(System.in);
        n = s.nextInt();

        int temp = n;
        /* n-1 if you do not want to include the original digit and
        n if you want to include original digit
         */
        for (int i = 0; i < length(n) - 1; i++)
        {

            temp = generate(temp);
            System.out.println(temp);
        }

    }
}

SSTF : in os subject

#include<stdio.h>
#include<conio.h>
#include<math.h>


void main()
{
    clrscr();
    int n;
    int arr[100];

    int curr_pos = 0;
    printf("Enter no of numbers; ");
    scanf("%d", &n);

    for (int i = 0; i < n; i + +)
    {

        printf("Enter no ", i + 1, ": ");
        scanf("%d", &arr[i]);
    }

    printf("\nEnter current position: ");
    scanf("%d", &curr_pos);
    int temp_n = n;

    int total = 0;
    for (int j = 0; j < temp_n; j++)
    {

        int diff = 0;
        int k = 0;

        int temp_k = 0;
        //  if(n>1){
        for (k = 0; k < n; k++)
        {

            int temp = abs(curr_pos - arr[k]);

            if (k == 0)
            {
                diff = abs(curr_pos - arr[0]);
            }

            if (temp <= diff)
            {
                temp_k = k;

                diff = temp;
                //    printf("\ntemp = %d",temp);
            }
        }
        k = temp_k;

        printf("\n%6d - %6d = %6d", curr_pos, arr[temp_k], abs(arr[temp_k] - curr_pos));

        total = total + abs(arr[temp_k] - curr_pos);

        curr_pos = arr[temp_k];
        for (int l = temp_k; l < n; l++)
        {

            arr[l] = arr[l + 1];
        }
        n--;
    }

    printf("\n\n\Total is : %d", total);

    getch();
}

FCFS : in OS subject

#include

#include

#include

void main()

{

clrscr();

int n;

int arr[100];

int curr_pos=0;

printf("Enter no of numbers; ");

scanf("%d",&n);

//int i;

//i=0;

for(int i=0;i<n;i++)

{

printf("Enter no " , i+1 , ": " );

scanf("%d",&arr[i]);

}

/* for(int j=0;j<n;j++)

{

printf("\n%d\n",arr[j]);

}*/

printf("\nEnter current position: ");

scanf("%d",&curr_pos);

int temp=curr_pos;

int total = 0;

for(int k=0;k<n;k++)

{

printf("%6d to %6d = %6d ms\n", temp, arr[k], abs(temp-arr[k]));

total = total + abs(temp-arr[k]);

temp = arr[k];

}

printf("\nTotal is : %d " , total);

getch();

}