number program

/*
Definition from Aniruddha Guddi:
It can be seen that the number, 125874, and its double, 251748, contain exactly the same digits, but in a different order.
Find the smallest positive integer, x, such that 2x, 3x, 4x, 5x, and 6x, contain the same digits.
 */


/**************************
 *   author: umang bhatt  *
 * bhatt.umang7@gmail.com *
 **************************/

#include<stdio.h>

#define TRUE 0
#define FALSE 1 


int contains_same_digits(int no1, int no2)
{
    int arr1[10] = {0};

    int arr1_top = -1;
    int arr2[10] = {0};

    int arr2_top = -1;
    int temp = no1;

    int i, j, k;
    int returnval;

    int flag = FALSE;

    //store numbers in array
    while (temp > 0)
    {

        arr1[++arr1_top] = temp % 10;
        temp = temp / 10;
    }

    temp = no2;
    while (temp > 0)
    {

        arr2[++arr2_top] = temp % 10;
        temp = temp / 10;
    }





    for (i = 0; i <= arr1_top; i++)
    {

        flag = FALSE;
        for (j = 0; j <= arr2_top; j++)
        {

            if (arr1[i] == arr2[j])
            {
                flag = TRUE;

                // remove that element from both arrays
                for (k = i; k < arr1_top; k++)
                {

                    arr1[k] = arr1[k + 1];
                }
                arr1_top--;

                for (k = j; k < arr2_top; k++)
                {

                    arr2[k] = arr2[k + 1];
                }
                arr2_top--;


                if (j != 0)
                    j--;
            }
        }

        if (flag == TRUE)
        {
            i = -1;
        }
    }

    if (arr1_top == -1 && arr2_top == -1)
    {
        returnval = TRUE;
    }

    else
    {
        returnval = FALSE;
    }
    return returnval;
}

int main()
{
    char c[5];
    int i, j;

    int flag;
    int flag1;

    for (j = 2; j <= 6; j++)
    {

        i = 1;
        flag = FALSE;
        while (flag == FALSE)
        {

            flag = contains_same_digits(i, (i * j));
            if (flag == TRUE)
            {

                printf("\n %d * %d = %d where digits of %d and %d are same  ", i, j, (i * j), i, (i * j));

                flag = TRUE;
            }
            i++;
        }
    }
    printf("\n");

    return 0;
}